Definition of algebra equation picture
y-y1=m(x-x1) where m is the slope and (x1-y1) is a point on the straight line in algebra.
The form is called point-slope form because you use the point and the
slope. To write the straight equation of a straight line, you need at
least two pieces of information, the slope, and a point on the straight
line in algebra. The point on the straight line can be the y-intercept
or any other point. Once you have the information, substitute in
point-slope form in algebra.
In algebra, slope of the straight line of equation is y-y1=m(x-x1)
Example problems for algebra equation picture:
Example 1:
In algebra, write the equation of the straight line equation that passes through the point (3,5) and has a slope of -2.
Solution:
Substitute x1=3, y1=5, and the slope into the point-slope form of the equation of a straight line.
y-y1=m(x-x1)
y-5=-2(x-3)
This y-5=-2(x-3) is an answer to the problem. Sometime you will be
asked to give your answer in slope-intercept form. Use the answer you
found in point-slope form and change it into slop-intercept form.
y-5=-2(x-3)
y-5=-2x+3
y=-2x+8
The equation y-5=-2(x-3) in point-slope form is equivalent to y=-2x+8 in slope-intercept form.
Example 2:
Write the equation of the straight line that passes through the points
(3,-2) and (-2,-1). To write the equation of a line, you must have the
slope. Find the slope of the straight line using the slope formula.
Solution:
Slope= (Change in y)/(Change in x) = `(y_2-y_1)/(x_2-x_1)`=`(-1+2)/(-2-3)`=`-1/5`
Use the slope and one of the points in the point-slope form of the
equation of the straight line. It does not matter whether you use (3,-2)
or (-2,-1). The two answers are equivalent equations.
y-y1=m(x-x1) y-y1=m(x-x1)
y+2=`-1/5`(x-3) y+1=`-1/5`(x+2)
Either y+2=`-1/5`(x-3) or y+1=`-1/5`(x+2) is an acceptable answer if
the question does not ask you to give your answer in slope-intercept
form. Sometimes you may be asked to give your answer in slope-intercept
form.
y+2=`-1/5`(x-3) y+1=`-1/5`(x+2)
y+2=`-1/5`x+`3/5` y+1=`-1/5`x`-2/5`
y=`-1/5`x+`3/5`-2 y=`-1/5`x`-2/5`-1
y=`-1/5`x+`(3-10)/5` y=`-1/5`x`(-2-5)/5`
y=`-1/5`x`-7/5` y=`-1/5`x`-7/5
Practice problems for algebra equation picture:
Problem 1:
Write the equation of the straight line passing through the point
(-5,2) and (3,4), give your answer in slope-intercept form.
Answer: y=`1/4`x+`13/4`
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Problem 2:
Write the equation of a straight line that contains the point (3,3) and
has a slope of -2. Write the equation in slope-intercept form.
Answer: y=-2x+4
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